admin百科知識 2022-02-12 22:39:21 計算定積分∫(上限1下限-1) (2x^2+x^3*cosx)(1+√(1-x^2))dx計算定積分∫(上限1下限-1) (2x^2 x^3*cosx)/(1 √(1-x^2))dx網友廻答：匿名網友∵x^3*cosx/(1 √(1-x^2))是奇函數∴∫[x^3*cosx/(1 √(1-x^2))]dx=0故∴∫[(2x^2 x^3*cosx)/(1 √(1-x^2))]dx=2∫[x^2/(1 √(1-x^2))]dx ∫[x^3*cosx/(1 √(1-x^2))]dx=2∫[x^2/(1 √(1-x^2))]dx=2∫[x^2(1-√(1-x^... db標簽 生活常識_百科知識_各類知識大全»計算定積分∫(上限1下限-1) (2x^2+x^3*cosx)(1+√(1-x^2))dx
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