tan(A B)=(tanA tanB)/(1-tanAtanB) 網友廻答:
- sin(a b)=sinacosb sinbcosa
cos(a b)=cosacosb-sinasinb tan(a b)=sin(a b)/cos(a b),然後分[fèn]子分母同時除以cosacosb 那麽就有tan(A B)=(tanA tanB)/(1-tanAtanB)
網友廻答:
- tan(A B)=sin(A B)/cos(A B)=(sinAcosB sinBcosA)/(cosAcosB-sinAsinB)分[fèn]子,分母同時除以cosAcosB得:=(sinA/cosA sinB/cosB)/(1-sinAsinB/cosAcosB)=(tanA tanB)/(1-tanAtanB)
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