admin百科知識 2022-02-12 23:09:10 (1)求y=2sin2x+2sinx-1的值域 (2)求y=3-2cos(2x+π3),x∈[-π3,π6]的最值(1)求y=2sin2x 2sinx-1的值域 (2)求y=3-2cos(2x π/3),x∈[-π/3,π/6]的最值網友廻答:匿名網友y=2sin²x 2sinx-1= 2(sinx 1/2)^2-3/2-1≤sinx≤1-1/2≤sinx 1/2≤3/20≤(sinx 1/2)²≤9/4-3/2≤(sinx 1/2)²≤3/4值域【-3/2,3/4】y=3-2cos(2x π/3)x∈[-π/3,π/6]2x∈[-2π/3,π/3]2x π/3∈[-π/... db標簽 生活常識_百科知識_各類知識大全»(1)求y=2sin2x+2sinx-1的值域 (2)求y=3-2cos(2x+π3),x∈[-π3,π6]的最值
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