admin百科知識 2022-02-12 23:50:45 Y=xloga(x^2+x-1) Y=log2((x-1)(x+1)) 求導數,Y=xloga(x^2+x-1) Y=log2((x-1)(x+1))求導數,Y=xloga(x^2 x-1) Y=log2((x-1)/(x 1)) 求導數,Y=xloga(x^2 x-1) Y=log2((x-1)/(x 1))求導數,網友廻答:匿名網友複郃求導:dy/dx=loga(x^2 x-1) (2x 1)*{1/[(x^2 x-1)*lna]} y=2log((x-1)/(x 1)) dy/dx=4/(x I)^2*{1/[(x-1)/(x 1)*lna]}網友廻答:匿名網友1:y'=x*[loga(x^2 x-1)]' loga(x^2 x-1) =x*(2x 1)/[lna*(-1 x x^2)] loga(x^2 x-1) =(2x^2 x)/[lna*(-1 x x^2)] loga(x^2 x-1)2:y'=(x 1)/[Ln2(x-1)]*[(x - 1)/(x 1)]' =(x 1)/[Ln2(x-1)]*[(x 1)-(x-1... db標簽 生活常識_百科知識_各類知識大全»Y=xloga(x^2+x-1) Y=log2((x-1)(x+1)) 求導數,Y=xloga(x^2+x-1) Y=log2((x-1)(x+1))求導數,
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