![已知sin(π+a)=-12,計算cos(2π-a)和tan(a-7π),第1張 已知sin(π+a)=-12,計算cos(2π-a)和tan(a-7π),第1張](data:image/gif;base64,R0lGODlhAQABAAAAACH5BAEKAAEALAAAAAABAAEAAAICTAEAOw==)
已知sin(π a)=-1/2,計算cos(2π-a)和tan(a-7π)網友廻答:
- sin(π a)=-sina
sina=1/2
cosa=根號3/2或cosa=-根號3/2
tana=根號3/3或tana=-根號3/3
cos(2π-a)=cosa=根號3/2或-根號3/2
tan(a-7π)=tana=根號3/3或-根號3/3
網友廻答:
- cos(2π-a)=根號3/2
tan(a-7π)=根號3/3
網友廻答:
- sin(π a)=-sina=-1/2
sina=1/2
cos(2π-a)=cosa
=±√(1-sin^2a)
=±√(1-1/4)
=±√3/2
tan(a-7π)
=tana
=sina/cosa
=(1/2) / (±√3/2)
=±√3/3
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