admin百科知識 2022-02-13 3:56:15 計算:(a+b+c)^2m(a-b-c)^2m+1(c-a-b)^4m+3(c+b-a)^m+1計算:(a b c)^2m(a-b-c)^2m 1(c-a-b)^4m 3(c b-a)^m 1網友廻答:匿名網友(a+b-c)^2m(a-b-c)^2m 1(c-a-b)^4m 3(c b-a)^m 1=(a b-c)^2m·[-(b c-a)]^2m 1·[-(a b-c)]^4m 3·(b c-a)^m 1=[-(a b-c)^6m 3][-(b c-a)^3m 2=-(a b-c)^6m 3·(b c-a)^3m 2 db標簽 生活常識_百科知識_各類知識大全»計算:(a+b+c)^2m(a-b-c)^2m+1(c-a-b)^4m+3(c+b-a)^m+1
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