admin百科知識 2022-02-13 8:11:26 已知x(x-1)-(x^2-y)=2,求代數式3x^2+3y^22-3xy已知x(x-1)-(x^2-y)=2,求代數式3x^2 3y^2/2-3xy網友廻答:匿名網友x(x-1)-(x^2-y)=2,變爲y=x 2,∴3x^2 3y^2/2-3xy=3x^ (3/2)(x 2)^-3x(x 2)=(3/2)x^ 6. db標簽 生活常識_百科知識_各類知識大全»已知x(x-1)-(x^2-y)=2,求代數式3x^2+3y^22-3xy
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