admin百科知識 2022-02-13 19:07:03 不等式根號x-2x-1≤1的解集是?|x-2x-1|≤1的解集爲?不等式根號x-2/x-1≤1的解集是?|x-2/x-1|≤1的解集爲?網友廻答：匿名網友1，(x-1)^2=網友廻答：匿名網友√[(x-2)/(x-1)]≤1,0≤ (x-2)/(x-1)≤1,0≤1-1/(x-1)≤1,-1≤-1/(x-1)≤0,0≤1/(x-1)≤1,解得x≥2,原不等式的解集爲[2,＋∞)；|(x-2)/(x-1)|≤1,-1≤(x-2)/(x-1)≤1,-1≤1-1/(x-1)≤1,-2≤-1/(x-1)≤0,0≤1/(x-1)≤... db標簽 生活常識_百科知識_各類知識大全»不等式根號x-2x-1≤1的解集是?|x-2x-1|≤1的解集爲?
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