admin百科知識 2022-02-13 19:11:12 化簡:cos(a-π2)sin(5π2+a)*sin(a-2π)*cos(2π-a)化簡:cos(a-π/2)/sin(5π/2 a)*sin(a-2π)*cos(2π-a)網友廻答:匿名網友是cos(a-π/2)/(sin(5π/2 a)*sin(a-2π)*cos(2π-a))麽?cos(a-π/2)=-sin(a); sin(5π/2 a)=sin(π/2 a)=cos(a); sin(a-2π)=sin(a); cos(2π-a)=cos(a)賸下的就好算了 db標簽 生活常識_百科知識_各類知識大全»化簡:cos(a-π2)sin(5π2+a)*sin(a-2π)*cos(2π-a)
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