admin在0.1molL H2S中加入同躰積、同濃度的NaOH溶液,反應後溶液中各微粒的濃度關系錯誤的是A [Na+]>[HS-]>[OH-]>[H+]>[S2-]B [Na+]+[H+]=[HS-]+[OH-]+2[S2-]C [Na+]
![在0.1molL H2S中加入同躰積、同濃度的NaOH溶液,反應後溶液中各微粒的濃度關系錯誤的是A [Na+]>[HS-]>[OH-]>[H+]>[S2-]B [Na+]+[H+]=[HS-]+[OH-]+2[S2-]C [Na+],第1張](data:image/gif;base64,R0lGODlhAQABAAAAACH5BAEKAAEALAAAAAABAAEAAAICTAEAOw== "在0.1molL H2S中加入同躰積、同濃度的NaOH溶液,反應後溶液中各微粒的濃度關系錯誤的是A [Na+]>[HS-]>[OH-]>[H+]>[S2-]B [Na+]+[H+]=[HS-]+[OH-]+2[S2-]C [Na+],第1張")
A [Na ]>[HS-]>[OH-]>[H ]>[S2-]
B [Na ] [H ]=[HS-] [OH-] 2[S2-]
C [Na ]=[S2-] [H ] [HS-]
D [OH-]=[H ] [H2S]
答案&理由
A [Na ]>[HS-]>[OH-]>[H ]>[S2-]
B [Na ] [H ]=[HS-] [OH-] 2[S2-]
C [Na ]=[S2-] [H ] [HS-]
D [OH-]=[H ] [H2S]
答案&理由
![在0.1molL H2S中加入同躰積、同濃度的NaOH溶液,反應後溶液中各微粒的濃度關系錯誤的是A [Na+]>[HS-]>[OH-]>[H+]>[S2-]B [Na+]+[H+]=[HS-]+[OH-]+2[S2-]C [Na+],第2張](/statics/default/images/niming.jpg "在0.1molL H2S中加入同躰積、同濃度的NaOH溶液,反應後溶液中各微粒的濃度關系錯誤的是A [Na+]>[HS-]>[OH-]>[H+]>[S2-]B [Na+]+[H+]=[HS-]+[OH-]+2[S2-]C [Na+],第2張")
更新：支持中譯英日韓.jpg)
0條評論