![配制pH=7.21的緩沖溶液500ml,0.10MOL.NAH2PO4和0.20MOL.LNAOH各多少ML?(H3PO4:PKA2=7.21)加急,麻煩幫忙做下,,第1張 配制pH=7.21的緩沖溶液500ml,0.10MOL.NAH2PO4和0.20MOL.LNAOH各多少ML?(H3PO4:PKA2=7.21)加急,麻煩幫忙做下,,第1張](data:image/gif;base64,R0lGODlhAQABAAAAACH5BAEKAAEALAAAAAABAAEAAAICTAEAOw==)
配制pH=7.21的緩沖溶液500ml,0.10MOL.NAH2PO4和0.20MOL.LNAOH各多少ML?(H3PO4:PKA2=7.21)
加急,麻煩幫忙做下,網友廻答:
- 首先:pKa2=-lg([HPO4 2-][H ]/[H2PO4 -]) pH=-lg[H ]所以:pKa2=pH lg([HPO4 2-]/[H2PO4 -]) 對數的運算,要求:pH=7.21=pKa2 則lg([HPO4 2-]/[H2PO4 -])=0;[HPO4 2-]/[H2PO4 -]=1也就是要求加入堿後,[HPO4 2-]與[H...
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