admin百科知識 2022-02-13 23:04:47 設函數y=x^x+ln(arctan5x),求其導數dydx、微分dy設函數y=x^x ln(arctan5x),求其導數dy / dx、微分dy網友廻答:匿名網友y = e^(xlnx) ln[arctan(5x)]dy/dx = e^(xlnx)[lnx 1] 1/arctan(5x)*[1 (5x)^2]^(-1)*5= x^x[lnx 1] 5/{arctan(5x)[1 (5x)^2]}dy = [x^x[lnx 1] 5/{arctan(5x)[1 (5x)^2]}]dx db標簽 生活常識_百科知識_各類知識大全»設函數y=x^x+ln(arctan5x),求其導數dydx、微分dy
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