admin百科知識 2022-02-12 18:09:23 求函數y=(sinx-2)(sinx-1)的值域求函數y=(sinx-2)/(sinx-1)的值域網友廻答:匿名網友求函數y=(sinx-2)/(sinx-1)的值域ysinx-y=sinx-2,故得sinx=(y-2)/(y-1);(y-2)/(y-1)≦1.(1)(y-2)/(y-1)≧-1.(2)由(1)得(y-2)/(y-1)-1=(-1)/(y-1)≦0,即有1/(y-1)≧0,故得y>1.①由(2)得(y-2)/(y-1) 1=(2y-3)/(y-1)≧0,故得y db標簽 生活常識_百科知識_各類知識大全»求函數y=(sinx-2)(sinx-1)的值域
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