admin百科知識 2022-02-12 20:26:42 已知x2+x-1=0,則x3+2x2+2004=_.已知x2x-1=0,則x32x22004=______.網友廻答:匿名網友∵x2x-1=0,∴x2=-x 1,∴原式=x•x22x22004=x(-x 1) 2(-x 1) 2004=-x2 x-2x 2 2004=-(-x 1)-x 2006=2005.故答[dá]案爲2005. db標簽 生活常識_百科知識_各類知識大全»已知x2+x-1=0,則x3+2x2+2004=_.
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