化簡sin(π/2 α)cos(3π-α)tan(π α)/cos(π/2-α)cos(-α-π)網友廻答：
- [sin(π/2 α)cos(3π-α)tan(π α)]/[cos(π/2-α)cos(-α-π)]
=[cosα(-cosα)tanα)/[sinα(-cosα)] (應用誘導公式)
=[cosα(sinα/cosα)]/sinα
=1。
網友廻答：
- sin(π/2 α)cos(3π-α)tan(π α)/cos(π/2-α)cos(-α-π)
=[cosα*(-cosα)*tanα]/[sinα*(-cosα)]
=[-sinα*cosα]/[sinα*(-cosα)]
=1.
admincos(3π-α)tan(π+α)cos(π2-α)cos(-α-π).jpg "化簡sin(π2+α)cos(3π-α)tan(π+α)cos(π2-α)cos(-α-π),第1張")
0條評論